Difference between revisions of "TADM2E 1.1"

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<math>a + b < \min(a,b) \Leftrightarrow a < 0 \and b < 0</math>
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<math>a + b < \min(a,b) \Leftrightarrow a < 0 \and b < 0</math>
  
 
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If both ''a'' and ''b'' are negative, &lt;math&gt;a + b &lt; min(a, b)&lt;/math&gt;. For example
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If both ''a'' and ''b'' are negative, <math>a + b < min(a, b)</math>. For example
  
       &lt;math&gt;a = -5&lt;/math&gt;
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       <math>a = -5</math>
       &lt;math&gt;b = -7&lt;/math&gt;
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       <math>b = -7</math>
       &lt;math&gt;a+ b = -5 + (-7) = -12&lt;/math&gt;
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       <math>a+ b = -5 + (-7) = -12</math>
       &lt;math&gt;min(-5, -7) = -7&lt;/math&gt;
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       <math>min(-5, -7) = -7</math>
  
  
 
[[introduction-TADM2E|Back to ''Introduction ...'']]
 
[[introduction-TADM2E|Back to ''Introduction ...'']]

Latest revision as of 18:24, 11 September 2014

$ a + b < \min(a,b) \Leftrightarrow a < 0 \and b < 0 $


If both a and b are negative, $ a + b < min(a, b) $. For example

     $ a = -5 $
     $ b = -7 $
     $ a+ b = -5 + (-7) = -12 $
     $ min(-5, -7) = -7 $


Back to Introduction ...