# Difference between revisions of "TADM2E 2.33"

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Ccamenares (Talk | contribs) (For row 1, the sum is 1. So, the formula 3^n is incorrect. Instead, 3^(n-1) is correct.) |
Ccamenares (Talk | contribs) |
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− | On careful observation , one can see that the sum of any row is just <math>3^(n-1)</math> | + | On careful observation , one can see that the sum of any row is just <math>3^<sup>(n-1)</sup></math> |

this is the sum for the series . This can even be computed using a series as shown below | this is the sum for the series . This can even be computed using a series as shown below | ||

## Revision as of 14:42, 2 March 2015

On careful observation , one can see that the sum of any row is just $ 3^<sup>(n-1)</sup> $ this is the sum for the series . This can even be computed using a series as shown below

1=a0 1 1 1 a1 a0 a2

now a(mid) of the next line becomes the a(0) +a(1) +a(2) that it this mid element is always the sum of the middle three elements