# Difference between revisions of "TADM2E 3.12"

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− | Let's put into the black box whole set | + | Let's put into the black box whole set <math>S=\{x_i\}_{i=1}^n</math>. If <math>bb(S)</math> is True, then such a subset exists and we can go on: |

# R:=S | # R:=S | ||

# for i:=1 to n do | # for i:=1 to n do | ||

− | ## If | + | ## If <math>bb(R/\{x_i\})</math> is True then <math>R:=R/\{x_i\}</math> |

When this iteration is finished R will be subset of S that adds up to k. | When this iteration is finished R will be subset of S that adds up to k. | ||

+ | |||

+ | This above solution assumes that there is only a single subset of S that adds to k. |

## Latest revision as of 21:37, 24 January 2019

Let's put into the black box whole set $ S=\{x_i\}_{i=1}^n $. If $ bb(S) $ is True, then such a subset exists and we can go on:

- R:=S
- for i:=1 to n do
- If $ bb(R/\{x_i\}) $ is True then $ R:=R/\{x_i\} $

When this iteration is finished R will be subset of S that adds up to k.

This above solution assumes that there is only a single subset of S that adds to k.