TADM2E 3.5

From Algorithm Wiki
Revision as of 05:06, 29 December 2016 by Joky (Talk | contribs)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to: navigation, search

1: Each node is identical, so the ratio of data over total should be:

$ \frac{Data}{Data + 3*Pointers} = \frac{4}{4 + 3*4} = \frac{1}{4} $

2: In a full tree, given n leaf nodes, there are n-1 internal nodes. Both leaf and internal nodes are worth 4 bytes:

$ \frac{\text{Size of Leafs}}{\text{Size of Leaf} + \text{Size of Internal Nodes}} = \frac{4 * n}{4*n + 4*(n-1)} = \frac{n}{2n-1} = \frac{1}{2} (n\to\infty) $