Difference between revisions of "TADM2E 4.23"
Latest revision as of 18:13, 11 September 2014
4-23. We seek to sort a sequence S of n integers with many duplications, such that the number of distinct integers in S is O(log n). Give an O(n log log n) worst-case time algorithm to sort such sequences.
With a self-balancing binary search tree, we can achieve O(log k) search and insertion (where k is the number of elements in the tree).
1. For each element in the sequence S, try and insert it into the tree.
- If the element is present, we increment a count variable stored at a node.
- If the element is not present, we insert the node and set the count = 1.
2. Traverse the tree in order and add elements according to the count.
Since the tree is guaranteed not to exceed log n elements, search and insertion take O(log log n).
Thus, this entire algorithm takes O(n * log log n + log n) = O(n * log log n) as required.