2.13

because [math]\displaystyle{ n^2 \lt = 2^n }[/math] for every n greater than 4 . Hence, we can say that [math]\displaystyle{ n^2 \lt = C* 2^n }[/math] for every n>=4 and so [math]\displaystyle{ n^2 = O(2^n) }[/math] .

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