TADM2E 2.33 - Revision history

Matt: Matt moved page User:TADM2E 2.33 to TADM2E 2.33 over redirect: revert

2020-08-02T12:07:03Z

Matt moved page User:TADM2E 2.33 to TADM2E 2.33 over redirect: revert

FuckyouMatt: FuckyouMatt moved page TADM2E 2.33 to User:TADM2E 2.33

2020-08-02T07:40:15Z

FuckyouMatt moved page TADM2E 2.33 to User:TADM2E 2.33

Manish.khkr at 15:56, 16 December 2019

2019-12-16T15:56:17Z

Ccamenares at 14:43, 2 March 2015

2015-03-02T14:43:44Z

Ccamenares at 14:42, 2 March 2015

2015-03-02T14:42:58Z

Ccamenares: For row 1, the sum is 1. So, the formula 3^n is incorrect. Instead, 3^(n-1) is correct.

2015-03-02T14:41:30Z

For row 1, the sum is 1. So, the formula 3^n is incorrect. Instead, 3^(n-1) is correct.

Algowikiadmin: Recovering wiki

2014-09-11T18:24:13Z

Recovering wiki

New page

On careful observation , one can see that the sum of any row is just <math>3^n</math>
this is the sum for the series . This can even be computed using a series as shown below

1=a0
1 1 1
a1 a0 a2

now a(mid) of the next line becomes the a(0) +a(1) +a(2) that it this mid element is always the sum of the middle three elements

← Older revision		Revision as of 15:56, 16 December 2019
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	now a(mid) of the next line becomes the a(0) +a(1) +a(2) that it this mid element is always the sum of the middle three elements		now a(mid) of the next line becomes the a(0) +a(1) +a(2) that it this mid element is always the sum of the middle three elements
		+
		+
		+	'''Alternate explanation :'''
		+
		+	Every element in the current row will be used 3 times in next row; once directly below it, and also in left and right element below it.
		+
		+	So sum of elements in <math>(n+1)</math>th row will be 3*(sum of elements in <math>n</math>th row).
		+
		+	Hence, S(n) = <math>3^{n-1}</math> (Base case : For 1st row, sum is 1)

← Older revision		Revision as of 14:43, 2 March 2015
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−	On careful observation , one can see that the sum of any row is just <math>3^~~<sup>(~~n-1~~)</sup>~~</math>	+	On careful observation , one can see that the sum of any row is just <math>3^{n-1}</math>
	this is the sum for the series . This can even be computed using a series as shown below		this is the sum for the series . This can even be computed using a series as shown below

← Older revision		Revision as of 14:42, 2 March 2015
Line 1:		Line 1:
−	On careful observation , one can see that the sum of any row is just <math>3^(n-1)</math>	+	On careful observation , one can see that the sum of any row is just <math>3^<sup>(n-1)</sup></math>
	this is the sum for the series . This can even be computed using a series as shown below		this is the sum for the series . This can even be computed using a series as shown below

← Older revision		Revision as of 14:41, 2 March 2015
Line 1:		Line 1:
−	On careful observation , one can see that the sum of any row is just <math>3^n</math>	+	On careful observation , one can see that the sum of any row is just <math>3^(n-1)</math>
	this is the sum for the series . This can even be computed using a series as shown below		this is the sum for the series . This can even be computed using a series as shown below

← Older revision	Revision as of 12:07, 2 August 2020
(No difference)

← Older revision	Revision as of 07:40, 2 August 2020
(No difference)