2.47

Change the assumptions of the proof.

The paper mentioned is "S. Skiena. Encroaching lists as a measure of presortedness. BIT, 28:775-784, 1988."

Other solution :

$O(nlog({\sqrt {n}}))$ and $O(nlog(n))$ belongs to same class of function with respect to Big O notation. There is no difference between them other than a constant factor.

$\lim _{x\to \infty }(nlog({\sqrt {n}}))/(nlog(n))$ = $\lim _{x\to \infty }1/2*(nlog(n))/(nlog(n))$ = $1/2$

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